## Uniform Circular Motion (UCM)

Consider an object moving along a circular path with constant or uniform speed. This might be a guest on a carousel at an amusement park, a child on a merry-go-round at a playground, a car with lost driver navigating a round-about or "rotary", a yo-yo on the end of a string, a satellite in a circular orbit around Earth, or Earth in its (nearly) circular orbit around out Sun.

As an object travels in a circle, the

directionof its velocity changes. Even tho' thespeed remains univorm,thevelocity changesbecause its direction changes.v=v_{2}-v_{1}This is

not zero, even tho'| v_{2}| = v_{2}= |v_{1}| = v_{1}= vv is the

speed, which remains constant. You can seevfrom the following diagram:Notice the two

similar trianglesin the position vectors and the velocity vectors,or

or

Since these are

similar triangles,we know thatv / v = r / r For small changes in time or for small angles , the distance r is very nearly given by

r = v t This means

v / v = r / r v / v = v t / r

v = v

^{2}t / rv /t = v

^{2}/ rv /t is the acceleration an object has because it moves in a circle; this is called the

centripetal accelerationa_{c}and is directed toward the center of the circle. That is,a _{c}= v^{2}/ r

Angular velocityHow fast is something turning or rotating or revolving? We call this its

angular velocityand give it the symbol , the lower case Greek letteromega. It may have units of revolutions per minute or revolutions per second or, better yet, radian per second.Most of us are comfortable measuring an angle in degrees. But measuring an angle in

radiansis usually more useful.While we can measure the angle in degrees using a protractor, there is another way to measure or define this angle. This -- or any other -- angle can me defined as the ratio of the

arc length sto theradius r; that is,Such a definition means this measure of the angle has no dimensions. We have taken an arc length, measured in something like meters, and divided it by a radius, also measured in something like meters. However, since we expect dimensions or units, we call this unit of angular measure a

radian. You may think ofradiansas added for cosmetic purposes! How large is a radian?Consider a complete circle. We would describe a complete circle as having an angle of 360

^{o}. In terms of radians, a complete circle has an arc length equal to its circumference, s = C = 2 r.What does all this have to do with uniform circular motion? The arc length traveled by a point on a rotating object is equal to the radius of that point multiplied by the angle through which it has rotated,

s = r when is measured in radians

That means the linear speed v of a point on a rotating object is equal to the radius of that point multiplied by the angular speed with which it is rotating, provided is measured in radians per time. That is,

v = r provided is measured in

radianspertime.

ExampleAn audio CD rotates at 150 rpm (revolutions per minute). What is the linear speed of a small scratch on the CD that is 10 cm from the center?

v = r v = (10 cm) (150

^{rev}/_{min}) [ 2^{rad}/_{rev}] [^{min}/_{ 60 s}]v = 157 cm / s

Example

Calculate the centripetal acceleration of our moon.It is in a nearly circular orbit of radius r = 3.84 x 10

^{8}m and has a period of 27.32 days.Our moon moves in a circle so its direction changes continually; that means it has an acceleration because its velocity changes; this is the

centripetal acceleration. From its radius and period we can find its speed and then calculate its centripetal acceleration.a _{c}= v^{2}/ rFirst we must find its speed v from the total distance traveled D divided by the time required T,

D = 2 r v = D / T

v = 2 r / T

v = [2(3.14) ( 3.84 x 10

^{8}m ) ]/ (27.32 da)][da/24h][h/3600s]v = 1 022 m / s

a

_{c}= v^{2}/ ra

_{c}= (1 022 m / s)^{2}/ 3.84 x 10^{8}ma

_{c}= 2.72 x 10^{-3}m / s^{2}= 2.72 mm / s^{2}

ExampleA rubber ball with mass of 50 grams is attached to a string one meter in length. What is the tension in the string if the ball moves in a circle on a horizontal, frictionless table with a constant speed of 4.2 m/s?

The vertical forces--the downward force of gravity (or weight) and the upward normal force of the table--cancel each other. The

tensionin the string provides the net force on the moving rubber ball. That net force causes the ball to move in a circle; it is the centripetal force, F_{c}= m v^{2}/ r.This is a direct application of F = m a since the tension in the string is the net force which is also the centripetal force,

F _{c}= m v^{2}/ rF

_{c}= ( 0.050 kg ) ( 4.2 m / s )^{2}/ (1.0 m)F

_{c}= 0.88 N(c) 2002, Doug Davis; all rights reserved

UCM ExamplesCurvesReturn to ToC, UCM & Gravity