BRAVO! That is correct.

The pressure in the hoist piston must be

P = W/A

P = Mg / A

P = [(1000 kg)(9.8 m/s2)] / [ R2 ]

P = [(1000 kg)(9.8 m/s2)] / [ (10 cm)2 ]

The pressure in the hydraulic pump is

P = F / A

P = F / [ r2 ]

P = F / [ (1 cm)2 ]

According to Pascal's Principle, these two pressures are the same

F / [ (1 cm)2 ] = [(1000 kg)(9.8 m/s2)] / [ (10 cm)2 ]

F = [ (1 cm)2 ] [(1000 kg)(9.8 m/s2)] / [ (10 cm)2 ]

F = [ (1 cm)2 ] [(1000 kg)(9.8 m/s2)] / [ (10 cm)2 ]

F = [ (1 )2 ] [(1000 kg)(9.8 m/s2)] / [ (10 )2 ]

F = [(1000 kg)(9.8 m/s2)] / [ (100 )]

F = 98 N

For comparison, remember the weight of the car is

W = M g = (1000 kg)(9.8 m/s2) = 9,800 N

This hydraulic hoist reduces the force necessary to lift the car by a factor of 100!

(c) 2000, Doug Davis; all rights reserved.