%%Zu -HKGOhg; Qޢdp 1150 Ex ?9.gifationeryrnetata12CWWPBOBODcd]H`U A! ?,H$,Ȥrl:ШtJZRvz[C.фVM>[рhP{mrn~t`}LTE Physics 1150 Exam #2 October 16, 1995 Name: _______________________ Possibly useful equations: w = mg Ff FN ac = v2/r Fc = m v2/r F = G Mm / r2 G = 6.67 x 1011 Nm2/kg2 ME = 6 x 1024 kg RE = 6,500 km W = F D cos q KE = (1/2) m v2 W = D KE = KEf DcTEXT ClarisWorks%%Z"ZTEXTpnot&STR 2v!ؿ!