BRAVO! That is correct.The pressure in the hoist piston must be

P = W/A P = Mg / A

P = [(1000 kg)(9.8 m/s

^{2})] / [ R^{2}]P = [(1000 kg)(9.8 m/s

^{2})] / [ (10 cm)^{2}]The pressure in the hydraulic pump is

P = F / A P = F / [ r

^{2}]P = F / [ (1 cm)

^{2}]According to Pascal's Principle, these two pressures are the same

F / [ (1 cm) ^{2}] = [(1000 kg)(9.8 m/s^{2})] / [ (10 cm)^{2}]F = [ (1 cm)

^{2}] [(1000 kg)(9.8 m/s^{2})] / [ (10 cm)^{2}]F = [ (1 cm)

^{2}] [(1000 kg)(9.8 m/s^{2})] / [ (10 cm)^{2}]F = [ (1 )

^{2}] [(1000 kg)(9.8 m/s^{2})] / [ (10 )^{2}]F = [(1000 kg)(9.8 m/s

^{2})] / [ (100 )]

F = 98 NFor comparison, remember the

weightof the car isW = M g = (1000 kg)(9.8 m/s ^{2}) = 9,800 NThis hydraulic hoist

reducesthe force necessary to lift the car by a factor of 100!(c) 2000, Doug Davis; all rights reserved.