## Summary

F _{bouyant}= w_{liquid}

_{ }

Severaldifferentsystems of units are in common useage when dealing with pressure:

1 pascal = 1 Pa = 1 [ N / m ^{2}]

1 atm = 1.013 x 10 ^{5}Pa

1 bar = 100 kPa = 1 x 10 ^{5}Pa

1 atm = 1.013 bar

1 atm = 101.3 kPa

1 mm Hg = 133 Pa

1 atm = 760 mm Hg

1 Torr = 1 mm Hg

1 atm = 760 Torr (Units of pounds per square inch (PSI) are also commonly used but we will avoid those in this course).

_{1}A_{1}v_{1}=_{2}A_{2}v_{2}For many situations -- for most situations involving a

liquidbut not a gas -- we can assume the density does not change. This is called anincompressible fluid.For those cases,A _{1}v_{1}= A_{2}v_{2}

(^{1}/_{2}) v^{2}+ P + g y = constantor

( ^{1}/_{2})_{1}v_{1}^{2}+ P_{1}+_{1}g y_{1}= (^{1}/_{2})_{2}v_{2}^{2}+ P_{2}+_{2}g y_{2}If the vertical height y does not change, this means

(

^{1}/_{2}) v^{2}+ P = constantor

( ^{1}/_{2})_{1}v_{1}^{2}+ P_{1}= (^{1}/_{2})_{2}v_{2}^{2}+ P_{2}(c) 2005, Doug Davis; all rights reserved

BouyancyHomeworkReturn to ToC, Fluids