No, I'm sorry; but that is not the right answer.

However, this is the answer you would get for a mass sliding down a frictionless inclined plane. That means you probably forgot to include the rotational Kinetic Energy.

Remember to include all the Kinetic Energy, both translational and rotational,

KErot = (1/2) I 2

 

(c) 2000, Doug Davis; all rights reserved.